what is the following sum 3 sqrt 125

These numbers are written  (a+b*i) Both   i   and   -i   are the square roots of minus 1Accordingly,√ -75  =                     âˆš 75 â€¢ (-1)  =                    âˆš 75  â€¢ âˆš -1   =                    Â±  âˆš 75  â€¢ i Can  âˆš 75 be simplified ?Yes! write the expression as a sum or difference of logarithms. For this reason we want to be able to find the coordinates of the vertex. Answer to: Determine whether the following series converges or diverges. Equations : Tiger Algebra gives you not only the answers, but also the complete step by step method for solving your equations x^3=125 so that you understand better The square root is 2√n (usually denoted √x ), the third (or cube) root is 3√n, the fourth root is 4√n and so on. How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? \( \Large (35)^{2} \div \sqrt[3]{125} + (25)^{2} \div 125 = ? Our math solver supports basic math, pre-algebra, algebra, trigonometry, calculus and more. Conclusion : Trinomial can not be factored. Both   i   and   -i   are the square roots of   -1 Since a square root has two values, one positive and the other negative   x2 + 5x + 25 = 0   has two solutions:  x = -5/2 + √ 75/4 •  i    or  x = -5/2 - √ 75/4 •  i Note that  âˆš 75/4 can be written as  âˆš 75  / √ 4   which is √ 75  / 2. Subtract  25  from both side of the equation :   x2+5x = -25Now the clever bit: Take the coefficient of  x , which is  5 , divide by two, giving  5/2 , and finally square it giving  25/4 Add  25/4  to both sides of the equation :  On the right hand side we have :   -25  +  25/4    or,  (-25/1)+(25/4)   The common denominator of the two fractions is  4   Adding  (-100/4)+(25/4)  gives  -75/4   So adding to both sides we finally get :   x2+5x+(25/4) = -75/4Adding  25/4  has completed the left hand side into a perfect square :   x2+5x+(25/4)  =   (x+(5/2)) â€¢ (x+(5/2))  =  (x+(5/2))2 Things which are equal to the same thing are also equal to one another. Truly, each term has two values and the sum has four values, in … This is a mistake. I come up with this by looking at dominant terms in the numerator and denominator of the nth term of the given series: Find a perfect square that is a multiple of 18: in this case it would be 9, because 9 x 2 = 18. I would limit compare to #sum1/sqrt(n)#.. Root plot for :  y = x2+5x+25 Axis of Symmetry (dashed)  {x}={-2.50}  Vertex at  {x,y} = {-2.50,18.75}  Function has no real roots var c=document.getElementById("myCanvas");var 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Each number under the root symbol ) 125 = 5 ×25 = 5 ×25 = ×25...

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